b^2=1089

Solution for b^2=1089 equation:

b^2=1089

We move all terms to the left:

b^2-(1089)=0

a = 1; b = 0; c = -1089;
Δ = b2-4ac
Δ = 02-4·1·(-1089)
Δ = 4356
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{4356}=66$
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-66}{2*1}=\frac{-66}{2}
=-33
$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+66}{2*1}=\frac{66}{2}
=33
$